If anyone can help with that, thank you very much I know I need to find the trapezium's area but can't find the length of its sides without just guessing. Any brain around to help? 
Maths Problem

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Peew971 6,326 posts
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Registered 11 years ago 
grey_matters 4,035 posts
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Registered 10 years agoLet x be the longest side, y be the shorter one, and z the width.
x + y = 30
x + z = 24
x = 2z (2 widths line up with the long side)
So,
x = 24  z (rearranging the second equation)
which means:
2z = 24  z (because x = 2z)
> z = 8 (and x = 16, y = 14)
You can probably do the rest yourself.
Edited by grey_matters at 18:53:12 17022013 
Peew971 6,326 posts
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Registered 11 years agoGreat! I got those first 2 equations but didn't notice the long side being twice the width so I got stuck there.
Thanks a lot 
Help!
http://i.imgur.com/0sIzcsW.png
I'm useless at maths and I need to know how to answer these questions. It is the working I need. (not for me but I can't think of anyone else to run to!)
Edited by mowgli at 21:21:45 20052013 
Anyone?
Wife needs to know for an exam in a couple of days and I'm fucking useless at maths 
chopsen 18,056 posts
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chopsen 18,056 posts
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Registered 11 years agoDoes that work? 
chopsen 18,056 posts
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Registered 11 years agoHah. Awesomes. 
RichieTenenbaum 2,286 posts
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Registered 5 years ago6) K=3 (2 squared is 4. Multiply by 3 to get 12. 3 to get 12)
7) (x + 2)^2 3 (shifted left by 2, down by 3) (it's plus 2 as you need x to be 2 to get back to zero and make y 3)
8) x = 1
max at 1,1 
chopsen 18,056 posts
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Registered 11 years agoYeah. But mine's prettier. 
RichieTenenbaum 2,286 posts
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Registered 5 years agoIt is.
MUCH. 
RichieTenenbaum 2,286 posts
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Registered 5 years agoSo, can we just type laTex into this forum? 
X201 17,256 posts
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Registered 10 years agoRichieTenenbaum wrote:
You've never used the search function on here have you?
So, can we just type laTex into this forum? 
chopsen 18,056 posts
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Registered 11 years agoI went via this website, that coverts latex to a linkable gif:
http://www.texify.com/links.php
I was tempted to just paste some latex and see what happens, but I thought that might be overestimating poor old craigy 
chopsen 18,056 posts
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Registered 11 years ago\[\sum\limits_{i = 1}^n {X_i^2} \]
edit: no
Edited by Chopsen at 21:48:52 20052013 
mrpon 31,857 posts
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Registered 10 years agoRichieTenenbaum wrote:
Afraid not, google: "mwnin laTex" for the syntax.
So, can we just type laTex into this forum? 
Genuine thanks, she says it helps a lot (looks like fucking alien talk to me). She doesn't know how you got the answer for 8 though? 
chopsen 18,056 posts
Seen 4 days ago
Registered 11 years agoat x = 1, the (x+1)^2 is equal to zero. All other values for x are going to be symmetrical around this. Raising something to the power of 2 "removes" the sign.
So the axis of symmetry is x= 1.
edit: why do I care?
Edited by Chopsen at 22:07:32 20052013 
speedofthepuma 13,389 posts
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Registered 10 years agoI used to know all this. How the hell does it stick in your stupid brain? You must be horribly deficient in some other way Chopsen. 
chopsen 18,056 posts
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Registered 11 years agoIt's only because I am actually doing some maths part time at the moment. I generally can't remember anything from more than a couple of weeks ago unless it's written down otherwise. 
RichieTenenbaum 2,286 posts
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Registered 5 years agoYou need to edit a sign there, Choppo 
RichieTenenbaum 2,286 posts
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Registered 5 years agoA better way to explain 8
x^2 is symmetrical around 0
(x+1)^2 must be symmetrical around 1. This makes the bracket 0.
When x is 1.
Then y = 1 + (1+1)^2 = 1 + (0)^2 = 1 
Thanks again, both. She was pulling her hair out and is now able to move on. 
Alastair 18,637 posts
Seen 22 hours ago
Registered 14 years agoI used to just about understand this sort of thing  did Maths Alevel but failed it.
I managed to work out 6 in my head. 7 I could have done on paper, 8 I would have struggled with. 
It take so much time to help you out 
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