If anyone can help with that, thank you very much I know I need to find the trapezium's area but can't find the length of its sides without just guessing. Any brain around to help? 
Maths Problem

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Peew971 4,791 posts
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Registered 9 years ago 
grey_matters 3,765 posts
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Registered 8 years agoLet x be the longest side, y be the shorter one, and z the width.
x + y = 30
x + z = 24
x = 2z (2 widths line up with the long side)
So,
x = 24  z (rearranging the second equation)
which means:
2z = 24  z (because x = 2z)
> z = 8 (and x = 16, y = 14)
You can probably do the rest yourself.
Edited by grey_matters at 18:53:12 17022013 
Peew971 4,791 posts
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Registered 9 years agoGreat! I got those first 2 equations but didn't notice the long side being twice the width so I got stuck there.
Thanks a lot 
Help!
http://i.imgur.com/0sIzcsW.png
I'm useless at maths and I need to know how to answer these questions. It is the working I need. (not for me but I can't think of anyone else to run to!)
Edited by mowgli at 21:21:45 20052013 
Shikasama 6,844 posts
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Registered 6 years agoI didn't even know what a trapezium was. 
Anyone?
Wife needs to know for an exam in a couple of days and I'm fucking useless at maths 
Chopsen 16,027 posts
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Chopsen 16,027 posts
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Registered 9 years agoDoes that work? 
Chopsen 16,027 posts
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Registered 9 years agoHah. Awesomes. 
RichieTenenbaum 2,211 posts
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Registered 4 years ago6) K=3 (2 squared is 4. Multiply by 3 to get 12. 3 to get 12)
7) (x + 2)^2 3 (shifted left by 2, down by 3) (it's plus 2 as you need x to be 2 to get back to zero and make y 3)
8) x = 1
max at 1,1 
Chopsen 16,027 posts
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Registered 9 years agoYeah. But mine's prettier. 
RichieTenenbaum 2,211 posts
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Registered 4 years agoIt is.
MUCH. 
RichieTenenbaum 2,211 posts
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Registered 4 years agoSo, can we just type laTex into this forum? 
X201 15,491 posts
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Registered 9 years agoRichieTenenbaum wrote:
You've never used the search function on here have you?
So, can we just type laTex into this forum? 
Chopsen 16,027 posts
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Registered 9 years agoI went via this website, that coverts latex to a linkable gif:
http://www.texify.com/links.php
I was tempted to just paste some latex and see what happens, but I thought that might be overestimating poor old craigy 
Chopsen 16,027 posts
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Registered 9 years ago\[\sum\limits_{i = 1}^n {X_i^2} \]
edit: no
Edited by Chopsen at 21:48:52 20052013 
mrpon 28,945 posts
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Registered 8 years agoRichieTenenbaum wrote:
Afraid not, google: "mwnin laTex" for the syntax.
So, can we just type laTex into this forum? 
Genuine thanks, she says it helps a lot (looks like fucking alien talk to me). She doesn't know how you got the answer for 8 though? 
Chopsen 16,027 posts
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Registered 9 years agoat x = 1, the (x+1)^2 is equal to zero. All other values for x are going to be symmetrical around this. Raising something to the power of 2 "removes" the sign.
So the axis of symmetry is x= 1.
edit: why do I care?
Edited by Chopsen at 22:07:32 20052013 
speedofthepuma 13,292 posts
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Registered 9 years agoI used to know all this. How the hell does it stick in your stupid brain? You must be horribly deficient in some other way Chopsen. I lurk. If I've spoken to you, I'm either impassioned, or drunk.

Chopsen 16,027 posts
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Registered 9 years agoIt's only because I am actually doing some maths part time at the moment. I generally can't remember anything from more than a couple of weeks ago unless it's written down otherwise. 
RichieTenenbaum 2,211 posts
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Registered 4 years agoYou need to edit a sign there, Choppo 
RichieTenenbaum 2,211 posts
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Registered 4 years agoA better way to explain 8
x^2 is symmetrical around 0
(x+1)^2 must be symmetrical around 1. This makes the bracket 0.
When x is 1.
Then y = 1 + (1+1)^2 = 1 + (0)^2 = 1 
Thanks again, both. She was pulling her hair out and is now able to move on. 
Alastair 15,807 posts
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Registered 13 years agoI used to just about understand this sort of thing  did Maths Alevel but failed it.
I managed to work out 6 in my head. 7 I could have done on paper, 8 I would have struggled with. 
It take so much time to help you out 
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