If anyone can help with that, thank you very much I know I need to find the trapezium's area but can't find the length of its sides without just guessing. Any brain around to help? |
XBL: Shadow Thi3f
PSN: Gold3nMoth
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If anyone can help with that, thank you very much I know I need to find the trapezium's area but can't find the length of its sides without just guessing. Any brain around to help? |
XBL: Shadow Thi3f
PSN: Gold3nMoth
Let x be the longest side, y be the shorter one, and z the width. x + y = 30 x + z = 24 x = 2z (2 widths line up with the long side) So, x = 24 - z (re-arranging the second equation) which means: 2z = 24 - z (because x = 2z) -> z = 8 (and x = 16, y = 14) You can probably do the rest yourself. Edited by grey_matters at 18:53:12 17-02-2013 |
Great! I got those first 2 equations but didn't notice the long side being twice the width so I got stuck there. Thanks a lot |
XBL: Shadow Thi3f
PSN: Gold3nMoth
Help! http://i.imgur.com/0sIzcsW.png I'm useless at maths and I need to know how to answer these questions. It is the working I need. (not for me but I can't think of anyone else to run to!) Edited by mowgli at 21:21:45 20-05-2013 |
Anyone? Wife needs to know for an exam in a couple of days and I'm fucking useless at maths |
Does that work? |
Hah. Awesomes. |
6) K=-3 (2 squared is 4. Multiply by 3 to get 12. -3 to get -12) 7) (x + 2)^2 -3 (shifted left by 2, down by 3) (it's plus 2 as you need x to be -2 to get back to zero and make y -3) 8) x = -1 max at -1,1 |
Yeah. But mine's prettier. |
It is. MUCH. |
So, can we just type laTex into this forum? |
RichieTenenbaum wrote:You've never used the search function on here have you? |
I went via this website, that coverts latex to a linkable gif: http://www.texify.com/links.php I was tempted to just paste some latex and see what happens, but I thought that might be overestimating poor old craigy |
\[\sum\limits_{i = 1}^n {X_i^2} \] edit: no Edited by Chopsen at 21:48:52 20-05-2013 |
RichieTenenbaum wrote:Afraid not, google: "mwnin laTex" for the syntax. |
Give me £5 I'm worth it.
Genuine thanks, she says it helps a lot (looks like fucking alien talk to me). She doesn't know how you got the answer for 8 though? |
at x = -1, the (x+1)^2 is equal to zero. All other values for x are going to be symmetrical around this. Raising something to the power of 2 "removes" the sign. So the axis of symmetry is x= -1. edit: why do I care? Edited by Chopsen at 22:07:32 20-05-2013 |
I used to know all this. How the hell does it stick in your stupid brain? You must be horribly deficient in some other way Chopsen. |
I lurk. If I've spoken to you, I'm either impassioned, or drunk.
It's only because I am actually doing some maths part time at the moment. I generally can't remember anything from more than a couple of weeks ago unless it's written down otherwise. |
You need to edit a sign there, Choppo |
A better way to explain 8 x^2 is symmetrical around 0 (x+1)^2 must be symmetrical around -1. This makes the bracket 0. When x is -1. Then y = 1 + (-1+1)^2 = 1 + (0)^2 = 1 |
Thanks again, both. She was pulling her hair out and is now able to move on. |
I used to just about understand this sort of thing - did Maths A-level but failed it. I managed to work out 6 in my head. 7 I could have done on paper, 8 I would have struggled with. |
It take so much time to help you out |
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